EULER (Numerical Version) - TI 85

Introduction
This program gives coordinates for an approximate solution for the differential equation ${\hbox{dy}\over \hbox{dx}}=\hbox{f(x,y)}$ using Euler's method.
 
If you have not used one of the programs posted on this website before, you should read through the information in the Intro to Programming section first.


The Program
:FnOff {FnOff is in GRAPH under Vars}
:Disp "INITIAL X"  {Disp and " are in PRGM under I/O}
:Input x  {Input is in PRGM under I/O} {x is the x-VAR}
:Disp "INITIAL Y" 
:Input y  {y is in GRAPH under Vars}
:Disp "STEP SIZE"    
:Input H 
:0$\to$ {The 0 is a zero}{The arrow is STO }
:Lbl Q  {Lbl is in PRGM under CTL}
:C+1$\to$
:x+H$\to$
:y+y1*H$\to$ {y1 is in VARS under EQU}
:Disp "STEP",C 
:Disp "X=", U  {The = is found on the STO button}
:Disp "Y=", V   
:Pause  {Pause is in PRGM under CTL}
:ClLCD  {ClLCD is in PRGM under I/O}
:U$\to$  
:V$\to$  
:Goto Q  {Goto is in PRGM under CTL}


Running the Program
 
You will need to enter a function f(x,y) into y1 before running the program. You can use the x and y shown in the GRAPH menu. The program will ask for an initial set of coordinates for x and y. You will also need to provide a stepsize. This can be either positive or negative. Hit ENTER to see the consecutive coordinates.
 
To test the program try the following:
  f(x,y)  =  x + y,   Initial x  =  1,  Initial y  =  1,  Stepsize  =  0.1
 
Your answer will be
X = 1.1,  Y = 1.2
X = 1.2,  Y = 1.43
X = 1.3,  Y = 1.693
X = 1.4,  Y = 1.9923
and so on